• BatmanAoD@programming.dev
    150·
    10 days ago

    Reminds me of quantum-bogosort: randomize the list; check if it is sorted. If it is, you’re done; otherwise, destroy this universe.

    • MajorHavoc@programming.dev
      32·
      10 days ago
      // portability

      Gave me the giggles. I’ve helped maintain systems where this portable solution would have left everyone better off.

  • Swedneck@discuss.tchncs.de
    32·
    10 days ago
    import yhwh  

def interventionSort(unsortedList):
    sortedList = yhwh.pray(
    "Oh great and merciful Lord above, let thine glory shine upon yonder list!", 
    unsortedList
    )  
    return sortedList
  • Allero@lemmy.today
    28·
    10 days ago

    The most beautiful thing about this program is that it would work.

    Various bit flips will once lead to all numbers being in the correct order. No guarantee the numbers will be the same, though…

    • 🔍🦘🛎@lemmy.worldEnglish
      6·
      9 days ago

      Reminds me of a program in Homestuck. It’s code that iterates until the author/universe dies, then executes some unknown code. The coding language is ~ath, or TilDeath.

    • ProgrammingSocks@pawb.social
      3·
      9 days ago

      Not necessarily. I don’t have the numbers in front if me, but there is actually a probability that, past that point, something is so unlikely that you can consider it to be impossible (I.e. will never happen within the lifetime of the universe)

    • Buddahriffic@lemmy.world
      2·
      9 days ago

      I’m not sure there’s any guarantee that it will ever be sorted, since bit flips will be random and are just as likely to put it more out of order than more in order. Plus if there’s any error correction going on, it can cancel out bit flips entirely until up to a certain threshold.

      Though I’m not sure if ECC (and other methods) write the corrected value back to memory or just correct the signals going to the core, so it’s possible they could still add up over time and overcome the second objection.

      • dan@upvote.au
        2·
        9 days ago

        ECC (and other methods) write the corrected value back to memory

        That was my understanding (it corrects the error and writes the good value back to RAM), but now I’m not so sure! I imagine it must do that, otherwise a second bit flip would actually corrupt the RAM, and the RAM manufacturer would want to reduce that risk.

        Regular ECC adds an extra parity bit for each byte. For each byte of memory, it can correct an error in one bit, and detect but not correct an error in two bits, so they wouldn’t want a one bit error to linger for longer than it needs to.

  • fluckx@lemmy.world
    24·
    9 days ago

    I prefer the one where you randomly sort the array until all elements are in order. ( Bogosort )

    • Ephera@lemmy.ml
      34·
      10 days ago

      I hear, it actually significantly increases the chance of the miracle occurring when you pass the array into multiple threads. It’s a very mysterious algorithm.

  • iAvicenna@lemmy.world
    14·
    9 days ago

    you can also call it quantum sort since there is non zero probability that it will sort itself by random flips

    • Comment105@lemm.ee
      61·
      9 days ago

      It would actually have happened an infinite amount of times already, if either the universe is infinite, or there are infinite universes.

      • CanadaPlus@lemmy.sdf.org
        2·
        9 days ago

        I really deeply hope the universe is finite for this reason. Every great or terrible thing always happens forever, there is no causality or consequence.

    • voldage@lemmy.world
      14·
      10 days ago

      I don’t think you can check if array of n elements is sorted in O(1), if you skip the check though and just assume it is sorted now (have faith), then the time would be constant, depending on how long you’re willing to wait until the miracle happens. As long as MTM (Mean Time to Miracle) is constant, the faithfull miracle sort has O(1) time complexity, even if MTM is infinite. Faithless miracle sort has at best the complexity of the algorithm that checks if the array is sorted.

      Technically you can to down to O(0) if you assume all array are always sorted.

  • TheOakTree@lemm.ee
    72·
    10 days ago

    Hello programmers…

    I recently took a course that went through basic python, C, and C++.

    I had a hard time implementing various forms of sorting functions by hand (these were exercises for exam study). Are there any resources you folks would recommend so that I can build a better grasp of sorting implementations and efficiency?

    • 90s_hacker@reddthat.com
      7·
      10 days ago

      Skiena’s Algorithm design manual is very widely recommended for learning algorithms, I’ve also heard good things about A common sense guide to algorithms and data structures. Skiena’s also has video lectures on YouTube if you prefer videos.

      From what I’ve seen, a common sense guide seems to be more geared towards newer programmers while Skiena assumes more experience. Consequently, Skiena goes into more depth while A common sense guide seems to be more focused on what you specifically asked for. algorithm design manual

      A common sense guide

    • AllHailTheSheep@sh.itjust.works
      3·
      9 days ago

      don’t get discouraged. sorting algorithms occur frequently in interviews, and yes you use them a decent amount (especially in languages without built in sorts like c) but they are one of the harder things to visualize in terms of how they work. I’d say avoid anything recursive for now until you can get selection and insertion down pat. check out geeksforgeeks articles on them, but also don’t be afraid to Google willy nilly, you’ll find the resource that makes it click eventually.

      in terms of efficiency, it does become a little more difficult to grasp without some math background. big o is known as asymptomatic notation, and describes how a function grows. for example, if you graph f1(x)=15log(x) and f2(x)=x, you’ll notice that if x is bigger than 19, then f2(x) always has a higher output value than f1(x). in computer science terms, we’d say f1 is O(log(n)), meaning it has logarithmic growth, and f2 is O(n), or linear growth. the formal definition of big o is that f(x) is O(g(x)), if and only if (sometimes abbreviated as iff) there exists constants N and C such that |f(x)| <= C|g(x)| for all x>N. in our example, we can say that C = 1, and N>19, so that fulfills definition as |15log(x)| <= 1|x| whenever x>19. therefore, f1(x) is O(f2(x)). apologies for just throwing numbers at you, (or if you’ve heard all this before) but having even just the most basic grasp of the math is gonna help a lot. again, in terms of best resources, geeksforgeeks is always great and googling can help you find thousands of more resources. trust that you are not the first person to have trouble with these and most people before you have asked online about it as well.

      I also highly reccomend grabbing a copy of discrete mathematics and it’s applications by Kenneth Rosen to dig farther into the math. there’s a few other types of asymptomatic notation such os big omega and big theta, even little o, that I didn’t mention here but are useful for comparing functions in slightly different ways. it’s a big book but it starts at the bottom and is generally pretty well written and well laid out.

      feel free to dm me if you have questions, I’m always down to talk math and comp sci.

      edit: in our example, we could also pick c =19 and n = 1, or probably a few other combinations as well. as long as it fills the definition it’s correct.